16
May
How much time does it take for the Porsche to catch the Honda?
Posted by: porscheadmin / Category: Porsche QuestionsTwo cars, a Porsche and a Honda, are traveling in the same direction, although the Porsche is 184 m behind the Honda. The speed of the Porsche is 23.9 m/s and the speed of the Honda is 17.9 m/s. How much time does it take for the Porsche to catch the Honda? [Hint: What must be true about the displacements of the two cars when they meet?]
Tags: Cars Honda, catch, Displacements, Honda, Honda Cars, much, Porsche, Porsche Cars, Same Direction, take, time, Traveling, Two Cars
May 16th, 2009 at 7:03 AM
Hey!
Here’s the entire answer to your question.
Let’s first identify the values we’re given:
d = distance Porsche is behind Honda = 184 m
V = speed of Porsche = 23.9 m/s
v = speed of Honda = 17.9 m/s
The “hint” in the problem asks what must be true about the displacements of the cars when they meet? Well, the displacements must be EQUAL if they meet:
displacement of Honda = displacement of Porsche
or
d(Honda) = d(Porsche)
Now let’s figure out what these displacements are. Assume that the INITIAL position of the Porsche is d = 0. Then:
d(Honda) = d + v*t
d(Porsche) = V*t
Now we equate these two values:
d + v*t = V*t
Here t = time, which is what we’re solving for. Rearranging terms to solve for t:
t = d / (V-v)
= 184 m / (23.9 m/s – 17.9 m/s)
= 30.66 seconds
So the Porsche will catch up to the Honda in 30.66 seconds. That’s your answer!
anaGah.
May 16th, 2009 at 7:38 AM
The basic formula would be vp * t = vh * t + x
Rewrite as t = x / (vp – vh) = 184 / (23.9 – 17.9) = 184 / 6 = 30.6 seconds.
May 16th, 2009 at 8:33 AM
Tiempo de alcance:
Ta = d / ( V1 – V2)…………………( V1 > V2 )
Ta = 184 / (23,9 – 17,9) = 30,67s
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